Assignemnt #117 and More Number Puzzle

Code

    ///Name: Daniel Tiffany-Appleton
    ///Period: 7
    ///Program Name: More Number Puzzle
    ///File Name: MoreNumberPuzzle
    ///Date Finished: 3/23/16
    
    import java.util.Scanner;
    
    public class MoreNumberPuzzle
    {
        public static void main( String args[] )
        {
            Scanner keyboard = new Scanner(System.in);
            
            int choice = 1;
            
            do
            {
                System.out.println(" ");
                System.out.println("1) Find two digit numbers <= 56 with sums of digits > 10");
                System.out.println("2) Find two digit number minus number reversed which equals sum of digits");
                System.out.println("3) Quit");
            
                choice = keyboard.nextInt();
            
                if( choice == 1 )
                {
                    LessThan56();
                }
            
                else if( choice == 2 )
                {
                    SelfMinusReverse();
                }
            
                else
                {
                    return;
                }
               
           }while (choice != 3);
            
        }
        
        public static void LessThan56()
        {
            System.out.println(" ");
            for( int x = 1; x <= 5; x++ )
            {
                for( int y = 1; y < 10; y++ )
                {
                    int num = (x*10)+y;
                    int sum = x + y;
                    
                    if( sum > 10 && num <= 56)
                    {
                        System.out.println("(" + x + "" + y + ")");
                    }
                }
            }
            return;
        }
        
        public static void SelfMinusReverse()
        {
            for( int y = 1; y < 10; y++ )
            {
                for( int z = 0; z < 10; z++ )
                {
                        int summ = y + z;
                        int number = (y*10)+z;
                        int inverseNum = (z*10)+y;
                        
                        if( number - inverseNum == summ )
                        {
                            System.out.println(" ");
                            System.out.println("(" + y + "" + z + ")");
                            return;
                        }
                }
            }
        }
    }

    

Picture of the output